What is the weight of 2 square feet of 22-gauge stainless steel?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $9.99Unlock all

Prepare for the Florida Roofing Trade Knowledge Test. Review essential roofing concepts with multiple choice questions and detailed explanations. Get ready for your certification!

Multiple Choice

What is the weight of 2 square feet of 22-gauge stainless steel?

Explanation:
Weight is found from density times volume. For a sheet, volume equals thickness times area. Convert the area to square inches: 2 ft^2 is 288 in^2. Use the thickness for 22-gauge stainless, which is about 0.032 inches. The volume is 288 × 0.032 = 9.216 cubic inches. Stainless steel density is about 0.284 lb per cubic inch, so the weight is 9.216 × 0.284 ≈ 2.62 pounds. Therefore, 2 square feet of 22‑gauge stainless steel weighs about 2.62 pounds.

Weight is found from density times volume. For a sheet, volume equals thickness times area. Convert the area to square inches: 2 ft^2 is 288 in^2. Use the thickness for 22-gauge stainless, which is about 0.032 inches. The volume is 288 × 0.032 = 9.216 cubic inches. Stainless steel density is about 0.284 lb per cubic inch, so the weight is 9.216 × 0.284 ≈ 2.62 pounds. Therefore, 2 square feet of 22‑gauge stainless steel weighs about 2.62 pounds.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy